Question

a boy standing in the middle of feel observe the flying bird in north and angle of elevation 30 degree and after and after two min he observe the same bird in south at an angle of elevetaion 60 degrree height 5-root 3 find speed of bird

Answer 1

Here the distance travelled by bird is d=x+y.
Also1.
$\frac{5 \sqrt{3} }{x} = tan30$
$and \: \frac{5 \sqrt{3} }{y} = \tan(60)$
so x=(5√3/tan30)=15
and y=(5√3/tan60)=5
now d=x+y=15+5=20
and speed=distance/time
=d/time=20/2=10metre/min