Question

. A boy standing on a horizontal plane finds a bird flying at a distance of 100m from him at an elevation of 300. A girl standing on the roof of 20m high building, finds the angle

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Answer 1

Answer:

ANSWER

Let A be the position of the bird and E and C be the positions of the girl and the boy, respectively.

Then,

∠ACB=30

o

,∠AED=45

o

,AC=100 m,EF=20 m

In right △ACB,

we have,

sin30

o

=

AC

AB

2

1

=

100

AB

AB=50 m

AD=AB−BD

AD=50−EF

AD=50−20=30 m

In right △ADE, we have,

sin45

o

=

AE

AD

2

1

=

AE

30

AE=30

2

=42.3 m

Therefore, the distance of bird from the girl is 42.3 m.