A boy standing on the gate of his house want to take a cycle 10 feet away but the boy moves three step forward Two Steps backwards and again three step forward and so on his each step is of one foot consider is going forward is one more and going back part is another moves then how many moves of reach his cycle?
Answers
Answered by
12
Answer:
if 1 step =1 foot then steps required
=(3+2)x10
=5x10
=50
:3+2 as he takes 5 steps instead of taking a single step
Answered by
2
Answer:
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Distance covered with 1 step = 1 m
Time taken = 1 s
Time taken to move first 5 m forward = 5 s
Time taken to move 3 m backward = 3 s
Net distance covered = 5 – 3 = 2 m
Net time taken to cover 2 m = 8 s
Drunkard covers 2 m in 8 s.
Drunkard covered 4 m in 16 s.
Drunkard covered 6 m in 24 s.
Drunkard covered 8 m in 32 s.
In the next 5 s, the drunkard will cover a distance of 5 m and a total distance of 13 m and falls into the pit.
Net time taken by the drunkard to cover 13 m = 32 + 5 = 37 s
I hope, this will explanation:
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