A boy stands on a cliff and throws a stone vertically upwards at time t=0 .The stone leaves his hand at 20m/s .Take the acceleration of the ball as 9.8m/s^2 show that the equation for the displacement of the ball is s=20t- 4.9t^2 what is the height of the stone 2.is art release and 6.0 after release
Answers
Answered by
1
Answer:
u don't know this answer of this question I am really sorry bro ok
Similar questions