Question

a boy starting from rest travels a distance of 200m in 10s .calculate the magnitude of accleration

Answer 1

distance = 200m.

time taken = 10s.

speed (v) = d/t = 200/10 = 20m/s

given, initial velocity (u) = 0 m/s

therefore acceleration = (v-u )/t

                                   = (20-0)/10

                                   = 20/10  = 2m/s^2