Question

A boy starts from his home at a certain time with
a certain speed to pick up his girlfriend from of-
fice at 5.00 pm. One day his girlfriend left the
office at 3.00 pm and start walking to home with
a speed of 40 km/hr and meet the boy in the way
who left his home at his usual time. They
reached home 40 min earlier than their usual
time. find the speed of boy.​

Answer 1

Answer:

150 km/Hr

Step-by-step explanation:

Total Time Saved = 40 min

This has the time to reach to office and coming back to that point where they meet

Hence time taken by boy from that point to office = 40/2 = 20 Min = 1/3 hr

Hence they meet 20 mins before 5 :00 PM = 4: 40 PM

Girl walked for 1 hr 40 min  = 5/3 hr

Speed of girl = 30 km/hr

Distance covered by girl = 30 * 5/3  = 50 km

Time taken by boy to cover 50 km = 1/3 hr

Speed of Boy = 50/(1/3) = 150 km/Hr

Answer 2

Answer:

Sayad apko es se help mile