Question

A boy starts from home and travels 60 m to the West and then turns at right angles towards the South. He
11 m and reaches the post office. How far is the post office from his home diagonally?
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Answer 1

Answer:

60.926m

Explanation:

Given:

• Boy travels 60m towards west.

• Turning a right angle towards south, he reached station.

To Find:

Distance diagonally.

Procedure:-

Let's take Distance towards west as AB = 60m

Distance towards south as BC = 11m

Using Pythagoras theorem we know that:

$\implies \sf AC^2 = AB^2 + BC^2$

$\implies \sf AC^2 = (60)^2 + (11)^2$

$\implies \sf AC^2 = 3600+121$

$\implies \sf AC^2 = 3712$

$\implies \sf AC = 60.926$

Distance from Diagonal = 60.926m

You need to know:

• Pythagoras theorem was stated by Pythagorean. They stated that base² + height² is always equal to hypotenuse². this was often called as Pythagoras triplet.

Answer 2

Given:

Boy first travels 60m towards West

Then travels 11m towards South

━━━━━━━━━━━━━━━━━

Need to find:

The distance of post office from home = XZ =?

━━━━━━━━━━━━━━━━━

Solution:

Clearly from the diagram, the triangle XYZ is a right angled triangle,

From Pythagoras theorem we know,

${hypotenuse}^{2} \: = {base}^{2} + {height}^{2}$

$\implies \: {xz}^{2} = {xy}^{2} + {yz}^{2}$

$\implies \: {xz}^{2} = {60}^{2} + {11}^{2}$

$\implies \: {xz}^{2} = 3600 + 121$

$\implies \: {xz}^{2} = 3721$

$\implies \: xz = \sqrt{3721}m$

$\red{\bold{\large{\boxed{ \implies \: xz = 61 m}}}}$