a boy stops after travelling 3 kilometer towards east and then goes 4 kilometer towards north along a plane road. The resultant displacement of the boy is?
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Answered by
3
the angle is 90° .
resultant displacement=√(3^2 + 4^2 + cos90°)
=√(9+16+0)=√25=5km
resultant displacement=√(3^2 + 4^2 + cos90°)
=√(9+16+0)=√25=5km
angelkavya01:
no u just report it
2. A ody moves over one fourth of a circular arc in a circle of radius r .The magnitude of distance travelled and displacement will be respectively
it is body
please
ask it in new questions arjun.
she is getting disturbed
please
sorry for that but this is book of questions
yes i know...bt u should ask it as a new question....u should not disturb others
ok then i will not ask questions again u can now relax
Answered by
3
N
l
l
l 4 km
________________l. E
3 km
according to Pythagoras theorem.....
3*(2) + 4*(2) = 25
resultant displacement = 5 km...
l
l
l 4 km
________________l. E
3 km
according to Pythagoras theorem.....
3*(2) + 4*(2) = 25
resultant displacement = 5 km...
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