Question

A boy stretches a stone against the rubber tane catapult or 'gulel (a device used to detach manpop<br />the tree by boys in Indian villages) through a distan<br />of 24 cm before leaving it. The tape returns to its norman<br />position accelerating the stone over the stretched length<br />The stone leaves the gulel with a speed 22 m/s. Assume that the acceleration is constant while the stone was being pushed by the tape, find its magnitude.​

Answer 1

Answer:

Correct Question:-

A boy stretches a stone against the rubber tape of a catapult or ‘gulel’ (a device used to detach mangoes from the tree by boys in Indian villages) through a distance of 24 cm before leaving it. The tape returns to its normal position accelerating the stone over the stretched length. The stone leaves the gulel with a speed of 2.2 m/s. Assuming that the acceleration is constant while the stone was being pushed by the tape, find it's magnitude.

Given:-

v = 2.2 m/s

u = 0 m/s

s = 24 cm = 0.24 m

where v means final velocity;

u means initial velocity

and s means distance.

To find:-

Magnitude of the stone.

Solution:-

Using Newton's third law of motion,

v$^2 {}$ – u$^2 {}$ = 2as

➝ (2.2)$^2 {}$ = 2 × a × 0.24

➝ 4.84/100 = 2 × a × 24/100

➝ 484/48 = a

➝ a = 121/12

➝ a = 10.1 m/s$^2 {}$

Therefore, magnitude = 10.1 m/s$^2 {}$.

Answer 2

Answer:

10.1m/s-2 will be the correct answer hope it helps you