A boy throws 2 dice simultaneously. Calculate the probability of getting a total of 10
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Probability of the favourable event is 3/36 = 1/12
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n(S) = (36)
A = {(4,6),(5,5),(6,4)
n(A) = {3}
P(A) = n(A)÷n(S)
P(A) = 3÷36
P(A) = 1÷12
P(A) = 1 upon 12
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