Physics, asked by jpjitendra8327, 11 months ago

a boy throws a ball in air in such a manner that when the ball is at its maximum height he throw another ball . if the ball thrown with the time difference 1 secound then what is the maximum height attained by ball

Answers

Answered by hasita1114

1

Answer:

Hmax = 5m

Explanation:

t(time of ascent) = 1sec

t=u/g

u=10m/s

Hmax=u2/2g

=100/20

Hmax=5m

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