Physics, asked by Dppu5202, 1 year ago

A charged metallic bob of mass m and charge Q is in equilibrium in presence of electric repulsion by Q(fixed) as shown. Find Q

Answers

Answered by CarliReifsteck
2

Given that,

Mass of bob = m

Charge = Q

We need to calculate the value of Q

Using relation of electric force and gravitational force

F=\dfrac{kQ}{r^2}

\dfrac{Gm}{r^2}=\dfrac{kQ}{r^2}}

Where, m = mass of bob

Q = charge

Q=\dfrac{r^2Gm}{kr^2}

Q=\dfrac{Gm}{k}

Hence, The value of Q is \dfrac{Gm}{k}

Answered by gargimpk
5

Answer:

√(4π∈mg) L

Explanation:

Refer attachment

hope it helps

Attachments:
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