Question

a boy throws a ball upward which comes back in 10s.find the velocity of throw and height to which the ball rises up.(g=10ms-²)
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Answer 1

Answer:

Let suppose The ball goes up to height h and take time 5 sec according to question.. (g=10m/s²)

Initial velocity(u) is 0 of the ball

Now we know formula v= u + g×t

By putting value we get v=50m/s

So the velocity of throw is 50 m/s

Now use second EQ for finding height h

H=ut + ½gt²

H=0 + ½ × 10 × 5²

H=125m

Hence the ball rise up to height 125 m

Answer 2

Answer:

500m

Explanation:

time=10sec

g=10m/s2

v=gt

v=10m/s2×10sec

v=100m/s

velocity we got is 100m/s

h=1/2gt^2

h=1/2×10×10^2

h=1/2×1000

h=500m

height we got is 500m