Question

A boy throws a ball with a velocity of towards a wall which is at 1.2 m from boy where it hits at height h1. If the launch velocity is and h2 is the corresponding height then (consider, height of wall > h1 and h2) 1) h2> h1 2) h2=h1 3) h2

Answer 1

Answer:

Upward velocity v  

0

​  

=20m/s

Horizontal acceleration,a  

x

​  

=−4m/s  

2

 

we know, Time of flight, T=  

g

2v  

y

​  

 

​  

=  

g

2v  

0

​  

sinθ

​  

=4sinθ

Also,range R=v  

0x

​  

T+  

2

ax

​  

T  

2

 

0=20cosθT−2T  

2

 

2T  

2

=20cosθT

T=10cosθ

10cosθ=4sinθ

tanθ=  

4

10

​  

=2.5

θ=tan  

−1

(2.5)

Explanation: