CBSE BOARD X, asked by Aster254, 1 month ago

A boy took a piece of wire with a length of 20mm, diameter of 10mm and having a resistivity of 0.0785Ωm. He connected this wire to a cell and made a circuit. What do you think what must have been the potential difference if 5×10¹⁹ electrons flowed through the circuit in 10 seconds ? (Take π = 3.14)

Answers

Answered by anmolalkagupta
1

Answer:

sorry frnd idk please let me know answer if u get answer

Answered by anubhavsavur06
0

Answer:

not sure

Explanation:

So 1st take , R=P*l/A

i did dat

then we know that c = n*e (number of elcetrons into charge of one elcetron*

to find the chanrge then divide it by t (I=c/t)

Then we have I

H=Isquare*t*r

FRICK WE HAD TO TAKE PIE IN 3.14

anyways then do the kWH formula and voila!

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