Question

A boy travels 30 m towards North−West to point A and takes a left to travel another 70 m to point Β. At B, the boy turns left again to travel 30 m to point C. What was his
i) speed, if the total journey took him 30 min
ii) displacement
I will mark u brainliest . Please answer correctly

Answer 1

$\bf\huge\underline{\underline{ Given :- }}$

• A boy travels 30 m towards North−West to point A

• takes a left to travel another 70 m to point Β.

• the boy turns left again to travel 30 m to point C.

• the total journey took him 30 min

$\bf\huge\underline{\underline{ To \: Find:- }}$

• speed

• displacement

$\bf\huge\underline{\underline{ Answer :- }}$

• Distance = path length covered .

• $\red{\implies}$ Distance = OA + AB + BC

• $\red{\implies}$ Distance = 30 + 70 + 30

• $\red{\implies}$ Distance = 130 m

$\rule{10cm}{0.05cm}$

Speed

• Speed = $\sf \frac{Distance}{time}$

• time = 30 minute = 1800 s

• $\red{\implies}$ Speed = $\sf \frac{130}{1800 }$

• $\red{\implies \bf Speed = 0.072 m/s }$

$\rule{10cm}{0.05cm}$

Displacement

• Displacement = shortest straight line distance

• $\red{\implies}$ Displacement = OC

• $\red{\implies \bf Displacement = 70 m}$

$\rule{10cm}{0.05cm}$

NB :- Diagram is attached

Answer 2

Answer :

i) 0.722222222 m/s

ii) 70m towards southwest

Explanation:

i) To find the speed firstly we have the calculate the total distance

= 30m + 70m + 30m

= 130m

Secondly, we have to convert the 30mins to second because the the total distance here is in meters.

= 30 x 60 seconds

= 1800 seconds

_________________________________________________________

So, we have to put the formula $s=\frac{d}{t}$,

= $s=\frac{70}{1800}$

= s = 0.722222222 m/s

_________________________________________________________

ii) Displacement = shortest path between the initial and the final position

Displacement = OC = 70meters towards southwest

________________x x x x x x x x x x____________________________

Hope it helps you,

Rudra, please mark it as Brainliest.

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