Question

If x is the smallest 3 digit number which when divided by 5 leaves reminder 3 and y = 6x+5 , then how many minimum integers that can be inserted between x and y ?
EXPLAIN STEP BY STEP​

Answer 1

Answer:

520

Step-by-step explanation:

100 is the smallest 3 digit number

and also divisible by 5 then we will add 3 to it so that it leaves remainder after division

So, x = 103

Now , y = 6(103)+5 = 618+5 = 623

Since Y>X

therefore y-x = no. of integer

i.e. 623-103 = 520

I think 520 is correct answer!

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