Question

*A boy travels from position A to B covering 5 m distance in 5 seconds time. What is his velocity?*

1️⃣ 1 m/s
2️⃣ 0 m/s²
3️⃣ 1 km/hour
4️⃣ None of the above​

Answer 1

Answer :-

Given :-

• Distance travelled = 5 m
• Time taken = 5 sec

To Find :-

• Velocity

Solution :-

$\rm Velocity = \dfrac{Displacement}{Time}$

$\rm = \dfrac{5}{5}$

$\rm = 1 m/s$

$\boxed{\rm Velocity = 1 \: m/s}$

Additional information :-

➩ Acceleration - It is the rate of change of velocity per unit time.

$\rm a = \dfrac{v-u}{t}$

➩ Unit of acceleration - m/s²

➩ SI Unit of velocity - m/s

➩ CGS unit of velocity - cm/s

Answer 2

The velocity is 2ms-1 and the correct option is 4) None of the above.

Given:

A boy travels from position A to B covering a 5 m distance in 5 seconds.

To Find:

The velocity.

Solution:

To find the velocity we will follow the following steps:

As we know,

Velocity, acceleration and distance relations are given by:

V²-u² = 2as

Here, a is acceleration, v is the final velocity and a is the distance in SI units.

And u is the initial velocity which is 0 as it is started from rest.

But, acceleration is not given. so, we will calculate acceleration by the formula-

$s = ut + \frac{1}{2} a {t}^{2}$

$5 = 0 \times 5 + \frac{1}{2} a {(5)}^{2} = \frac{1}{2}25a \: = \frac{10}{25} a = 0.4m {s}^{ - 2}$

Now, put the value of acceleration in the above formula to find the velocity we get,

$v² - 0 = 2×0.4×5 =4$

$v = \sqrt{4} = 2m {s}^{ - 1}$

Henceforth, the velocity is 2ms-1 and the correct option is 4) None of the above.

#SPJ3