a boy uses spectacle of focal length -50 cm. name the defect he is suffering from. compute the power of his lens.
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Answered by
53
Because the focal lenth (f=-50cm) is negative, so it is a Diverging Lens.
Thus, the boy is suffering from “Myopia" or “Short Sightedness".
Focal Length (f) = -50cm = -(0.5)m
Now, Power of the lens =>
P = 1/f
P = 1/(-0.5)
P = -2 D....●
So, the power of the lens is -2 Diopter.
Please mark it as brainliest, if it was helpful.
Thus, the boy is suffering from “Myopia" or “Short Sightedness".
Focal Length (f) = -50cm = -(0.5)m
Now, Power of the lens =>
P = 1/f
P = 1/(-0.5)
P = -2 D....●
So, the power of the lens is -2 Diopter.
Please mark it as brainliest, if it was helpful.
Answered by
12
P = 1/f
P = 1/(-0.5)
P = -2 D...
So, the power of the lens is -2 Diopter.
Please mark it as the brainliest
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