ABCD is a square. A line BM intersects CD at M and the diagonal AC at O such that angle AOB =70°, find a .
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AOB = MOC = 80°. (vertically opposite angle)And, DMO = MOC + MCO.......(1)As we know that ...
MCO=45°
a=80°+45°=125°
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Answer:
AOB = MOC= 80°( Vertically opposite angle) And DMO
= MCO = MCO 1. as we know that
MCO= 45°
a= 80°+45° = 125°
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