Question

a boy walks 15 m due north and 12 m due east and then 12 south on a flat ground. How far away is he from the starting point?​

Answer 1

Answer:

the answer is 17m

Step-by-step explanation:

First the person moves from A to B and then B to C.

His distance from the starting point is AC.

AC can be calculated using Pythagoras Theorem.

Applying Pythagoras theorem

(AB)  

2

+(BC)  

2

=(CA)  

2

 

(15)  

2

+(8)  

2

=(x)  

2

 

225+64=(x)  

2

 

x  

2

=289

x=  

289

​

=17m

Hence the man is 17m from the starting point.

solution