Question

A boy walks 3 km towards east then 6 km towards north finally 5 km towards east again find the distance travelled and the displacement of boy

Answer 1

your required answer is as follows

Answer 2

Distance is the total path covered.
Displacement is the distance between initial and final position
$Distance = 3+6+5 = 14 \: \: km \\ Displacement = \sqrt{ {(3 + 5)}^{2} + {6}^{2} } \\ = \sqrt{100} = 10 \: \: km$