Question

A boy walks a distance of 30 m in 1 minute and
another 30 m in 1.5 minute. Describe the type of
motion of the boy and find his average speed
in ms-1​

Answer 1

Answer:

It is a uniform motion.

30+30=60

1+1.5=2.5

Average speed =Total distance/total time

=60/2.5

120ms^-1

Answer 2

​ Answer:

The boy is moving with non uniform speed

5/12 m/s

Explanation:

t₁=1 min=60 sec

t₂=1.5 min=90 sec

S₁=30 m

S₂=30 mv₁=S₁/t₁   =30/60   =1/2 m/s

v₂=S₂/t₂   =30/90   =1/3 m/s

Average velocity for the whole journey is given by ,

average speed=u+v/2

u+v/2= (1/2+1/3)/2        

=(5/6)/2        

=5/12 m/s

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