A boy walks to his school at a distance of 6km with a speed of 2.5km/h and walks back with constant speed of 5km/h. His average speed for round trip expressed in Km/h is?
Ans 10/3
solution?
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1
time TO; 6/2.5 = 2.4 = 2h24m
time BACK; 6/5 = 1.2 = 1h12m
average speed; 12 : ( 2.4 + 1.2 ) = 3.33' = 3⅓ km/h
Or
AVERAGE SPEED = TOTAL DISTANCE / TOTAL TIME
TOTAL DISTANCE = 6 +6 = 12 km
TOTAL TIME = 6/2.5 + 6/5 = 12/5 +6/5 = 18/5 = 3.6 hours
AVERAGE SPEED = 12 /3.6 = 120/36 = 10/3 = 3.33 km/ hour ANSWER
Or
time TO; 6/2.5 = 2.4 = 2h24m
time BACK; 6/5 = 1.2 = 1h12m
average speed; 12 : ( 2.4 + 1.2 ) = 3.33' = 3⅓ km/
Please mark me brainlist
time BACK; 6/5 = 1.2 = 1h12m
average speed; 12 : ( 2.4 + 1.2 ) = 3.33' = 3⅓ km/h
Or
AVERAGE SPEED = TOTAL DISTANCE / TOTAL TIME
TOTAL DISTANCE = 6 +6 = 12 km
TOTAL TIME = 6/2.5 + 6/5 = 12/5 +6/5 = 18/5 = 3.6 hours
AVERAGE SPEED = 12 /3.6 = 120/36 = 10/3 = 3.33 km/ hour ANSWER
Or
time TO; 6/2.5 = 2.4 = 2h24m
time BACK; 6/5 = 1.2 = 1h12m
average speed; 12 : ( 2.4 + 1.2 ) = 3.33' = 3⅓ km/
Please mark me brainlist
ranideepa848:
Time=distance1/Speed1+distance2/speed2
Answered by
2
frd yhi h kya pls tell me in comment apne to ans10/3 lika h but my ans is not that ....please check it
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