A boy was flying a kite which was at a height of 40m just above a tree. The string was 50m long. How far was the boy from the tree? The answer is 30m......explain me the method you have used. don't give wrong answers..
Answers
Answer:
30 meter away from the tree was the boy flying the kite.
Step-by-step explanation:
Given : A boy was flying a kite which was at a height of 40 m just above a tree. The string was 50 m long.
To find : How far away from the tree was the boy flying the kite?
Solution :
According to question,
A right angle triangle ABC is form in which,
Refer the attache figure below.
AB=50 m is the length of the string be the hypotenuse,
AC=40 m is the height of the boy to tree be the perpendicular,
BC=x is the distance between tree was the the boy flying the kite be the base.
Applying Pythagoras theorem,
AB^2=AC^2+BC^2AB2=AC2+BC2
50^2=40^2+x^2502=402+x2
2500=1600+x^22500=1600+x2
2500-1600=x^22500−1600=x2
900=x^2900=x2
x=\sqrt{900}x=900
x=30x=30
Therefore, 30 meter away from the tree was the boy flying the kite.
Answer:
AC=40 m is the height of the boy to tree be the perpendicular, BC=x is the distance between tree was the the boy flying the kite be the base. Applying Pythagoras theorem, Therefore, 30 meter away from the tree was the boy flying the kite.