Question

A boy weighing 60 kgf is wearing shoes with heels of area of cross section 20 cm square, while a
girl weighing 45 kgf is wearing sandals with heels of area of cross section 1.5 cm square.Compare the pressure exerted on the ground by their heels when they stand on the heel of
one foot. perfect answer with process will be marked as brainlist answer

quickly solve it please
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Answer 1

pressure exerted by girl heel will be more as area of heel is less . pressure is inversely proportional to the area of contact

Answer 2

Answer:

The pressure of the girl's heel is 10 times of boy's heel.

Explanation:

Given that,

Weight of boy = 60 kgf

Area of shoes = 20 cm²

Weight of girl = 45 kgf

Area of heel= 1.5 cm²

We need to calculate the pressure

Pressure exerted on the ground by the boy's shoes

Using formula of pressure

$P_{b}=\dfrac{F}{A}$

Put the value into the formula

$P_{b}=\dfrac{60}{20}$

$P_{b}=3\ kgf/cm^{2}$

Pressure exerted on the ground by the girl's heel

Using formula of pressure

Put the value into the formula

$P_{g}=\dfrac{45}{1.5}$

$P_{g}=30\ kgf/cm^{2}$

We need to calculate the ratio of the pressure P₁ and P₂

$\dfrac{P_{b}}{P_{g}}=\dfrac{3}{30}$

$P_{g}=10 P_{b}$

Hence, The pressure of the girl's heel is 10 times of boy's heel.