A boy went to his school at a speed of 12kmph and returned to his house at a speed of 8 kmph.If he has taken 50min for the whole journey what was the total distance walked.
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Answered by
9
Here Your Answer✍️
Boy Home➡️School=12 km /h
Boy School➡️Home=8 km/h
Total Time=50 min
Let Distance be=x
Time=Distance/time
First time+second time=Total Time
x/12+x/8=50/60 hours
2x+3x/24=50/60
5x/24=50/60
x=50/60×24/5
x=4 km
So
From home to School=4 km
School to home=4 km
Total=(4+4)=8 km
Total Distance➡️8 km
Boy Home➡️School=12 km /h
Boy School➡️Home=8 km/h
Total Time=50 min
Let Distance be=x
Time=Distance/time
First time+second time=Total Time
x/12+x/8=50/60 hours
2x+3x/24=50/60
5x/24=50/60
x=50/60×24/5
x=4 km
So
From home to School=4 km
School to home=4 km
Total=(4+4)=8 km
Total Distance➡️8 km
ankit8947:
your answer is wrong
Answered by
4
so the total distance walked is 4* 2 = 8 km
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