Math, asked by aryanpalverma, 11 months ago

A boy wishes to cut as many pieces of ropes of equal length as he
can from peices that are 35 m, 49 m. and 56 m, long. If he wants the pieces to be as long
as possible and does not like to waste any rope. how long should each be
And what the total number of pieces ?​

Answers

Answered by harsh85272720
1

Answer:

Hope this helps you............

Step-by-step explanation:

6m,7m,8m long is the answer


aryanpalverma: plz frame the statement
harsh85272720: ok Just a minute
Answered by sharonr
0

The total number of pieces is 7 and each should be of length 5 m , 7 m , 8 m

Solution:

Given that,

A boy wishes to cut as many pieces of ropes of equal length as he  can from pieces that are 35 m, 49 m. and 56 m, long

He wants the pieces to be as long  as possible and does not like to waste any rope

Which means, we have to find greatest common factor of 35 , 49 , 56

FIND GCF OF 35 , 49 , 56

The factors of 35 are: 1, 5, 7, 35

The factors of 49 are: 1, 7, 49

The factors of 56 are: 1, 2, 4, 7, 8, 14, 28, 56

Then the greatest common factor is 7

Thus the total number of pieces is 7

how long should each be

\frac{35}{7} = 5 \\\\\frac{49}{7} = 7 \\\\\frac{56}{7} = 8

Thus each should be 5 m , 7 m , 8 m

Learn more:

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