A brakes applied to a car produced an acceleration of 6 m/s square in opposite direction of motion . if the car takes two sec to stop . calculate the distance it travel to this time.
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we have to find the initial velocity.
v = u + at
0 = u - 6 * 2
u = 12m/s
now finding distance we use s = ut + 1/2 at2
s = 12 * 2 + 1/2 * (-6) * 2
s = 24 - 6
s = 18 m
hope it helped
v = u + at
0 = u - 6 * 2
u = 12m/s
now finding distance we use s = ut + 1/2 at2
s = 12 * 2 + 1/2 * (-6) * 2
s = 24 - 6
s = 18 m
hope it helped
sarika987:
but why we subtract 6 from 24
I think that 12 will be subtract from 24
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