A branch falls from the top of a 97.1-m-tall redwood tree, starting from rest. How fast is it moving when it reaches the ground? Express your answer with the appropriate units.
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HERE IS YOUR ANSWER
GIVEN :-
h = 97.1
u = 0 m/s^2
g = 9.8 m/s^2
v = ?
APPLYING KINEMATICS RELATION
V^2 = u^2 + 2 gh
v^2= (0)^2 + 2 (9.8) (97.1)
v^2 = 1903. 16
v= 43.62 m/s
HOPE IT'S HELP YOU ✌
GIVEN :-
h = 97.1
u = 0 m/s^2
g = 9.8 m/s^2
v = ?
APPLYING KINEMATICS RELATION
V^2 = u^2 + 2 gh
v^2= (0)^2 + 2 (9.8) (97.1)
v^2 = 1903. 16
v= 43.62 m/s
HOPE IT'S HELP YOU ✌
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