Question

A brass disc at 0°C has diameter 50 cm and hole of diameter 10cm. For brass linear expansion = 18×10^-6/°C. When the disc is heated to 100°C , the diameter of the hole becomes

Answer 1

Answer:

9.964

Explanation:

the difference of diameters = 40 cm = L

linear expansion = ∝LΔT =18×10^-6×40×100 = 72×10^-3= 0.072

the diameter of the hole becomes 10 - 0.072/2 = 10 -0.036 = 9.964cm

Answer 2

The diameter of hole after heated is 10.018 cm.

Explanation:

Given that,

Diameter of disc = 50 cm

Diameter = 10 cm

Linear expansion $\alpha=18\times10^{-6}/^{\circ}C$

Final temperature = 100°C

Initial temperature = 0°C

We need to calculate the diameter of hole after heated

Using formula for diameter

$l_{2}=l_{1}(1+a(t_{2}-t_{1}))$

Put the value into the formula

$l_{2}=10\times10^{-2}(1+18\times10^{-6}(100-0))$

$l_{2}=0.10018\ m$

$I_{2}=10.018\ cm$

Hence, The diameter of hole after heated is 10.018 cm.

Learn more :

Topic : Linear expansion

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