Question

a hollow garden roller 63 cm wide with a girth of 440 cm is made of 4 cm thick iron. find the volume of the iron.

Answer 1

hello....

▶▶Circumference of roller = 440 cm

▶▶2*Pi*R = 440 = R

▶(220*7/22) = 70 cm

▶▶Outer radius = 70 cm

▶▶inner radius
= 70-4 cm = 66 cm

▶▶Therefore Volume or iron = π [(70^2 - 60^2)]X63
simplifying...

▶= 58752 cm^3◀

thank you...

Answer 2

AnswEr:

Clearly, garden roller forms a cylinder of length h = 63 cm, circumference (girth) of one end = 440 cm. Let the external radius of the roller be R cm. Then,

$\tt \: 2\pi \: r = 440 \\ \\ \implies \sf 2 \times \frac{22}{7} \times r = 440 \\ \\ \implies \sf \: r = 70 \: cm$

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$\therefore$$\sf\orange{Internal\:radius\:(r)}$

$\sf = (70 - 4) = 66 \: cm$

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$\mathfrak{hence,}$$\sf\pink{Volume\:of\:the\:iron}$

$\sf = \pi( {r}^{2} - {r}^{2} )h \\ \\ \sf = \frac{22}{7} \times ( {70}^{2} - {66}^{2} ) \times 63 \: {cm}^{3} \\ \\ \sf = \frac{22}{7} \times 136 \times 4 \times 63 \: {cm}^{3} = 10 7712 \: {cm}^{3}$

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