Question

A brass rod I m long when heated through 80°C increases in length by 1.60 mm. The coefficient of linear expansion for the brass is​

Answer 1

Explanation:

from the formula∆l = l(alpha)∆T

0.0016 = 1 X 80 then X = 0.0002

so coefficient of linear expansion is 0.0002 k-1

Answer 2

Answer:

The coefficient of linear expansion of the brass rod is $2\times10^{-5} /*C$

Explanation:

Given that,A brass rod which is 1m long,increases its length by 1.60mm when it is heated through 80*C.We are required to find the coefficient of linear expansion of brass.

The coefficient of linear expansion is the ratio of change in length to the product of length and change in temperature.Hence,mathematically we write it as $\alpha=\frac{\delta l}{l\delta T}$

The initial length of rod=1m

Change in length of rod=1.6mm=0.0016m

Change in temperature=80°C

Substituting values in above relation,we get$\alpha=\frac{0.0016}{1\times80} =2\times10^{-5} /*C$

Therefore,the coefficient of linear expansion of the brass rod is found to be $2\times10^{-5} /*C$

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