Question

A break applied to a car produce an acceleration of 6m/s^ in the opposite direction to motion.if the car take 2 sec to stop after the applecation of breaks.calculate the distance trave during this tume

Answer 1

acceleration=6m/s^2
so retardation=-6m/s^2
Time=2sec
v=0 because car stops

now by 1st equation of motion v=u+at we get
0=u-6×2
12=u
now by 3rd equation of motion v square -usquare=2as we get
0^2-(12^2)=2×6×S
0-144=12S
-144/12=s
-12=s

so that the car will travel 12 m in the opposite direction of its motion.