A bredy of mass 40 kg wants the climb up the rope hanging vertically. The rope can withstand a maximum tension of 600N: The Manimum acceleration with which the boy can climb the rope
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Answer:
A bredy of mass 40 kg wants the climb up the rope hanging vertically. The rope can withstand a maximum tension of 600N: The Minimum acceleration with which the boy can climb the rope is 5 m/s².
Explanation:
Given: T max = 600 N
Mass = 40 kg
Find maximum acceleration.
Let be the acceleration with which the body can climb the rope
T man - mg = ma
substituting the value in the above equation we get :-
600 = 40 × ( 10 + a)
10 + a = 600/40
10 + a = 15 m/s
a = 15 - 10 = 5 m/s²
So, the manimum acceleration with which of the boy can climb the rope = 5 m/s².
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