Math, asked by chimatamadhuri123, 2 days ago

solve the differential equation cos(hx).dy/dx +y.sin(hx)=2cos(h^2x).sin(hx)

Answers

Answered by hanumantkalyankar
0

Answer:

please mark the brilliant

Step-by-step explanation:

Correct option is D)

cosxdy =y(sinx−y) dx

dx

dy

=ytanx−y

2

secx

y

2

dx

1dy

y

1

tanx =−secx

Let

y

−1

=t⇒

y

2

1

dx

dy

=

dx

dt

dx

dt

+t(tanx)=−secx=

dx

dt

+(tanx)t=secx.

I.F=e

∫tanxdx

=secx

Solution is t(I.F)=∫(I.F) secx dx

y

1

secx = tanx +c

Hence, option 'D' is correct.

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