solve the differential equation cos(hx).dy/dx +y.sin(hx)=2cos(h^2x).sin(hx)
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Answer:
please mark the brilliant
Step-by-step explanation:
Correct option is D)
cosxdy =y(sinx−y) dx
⇒
dx
dy
=ytanx−y
2
secx
⇒
y
2
dx
1dy
−
y
1
tanx =−secx
Let
y
−1
=t⇒
y
2
1
dx
dy
=
dx
dt
⇒
dx
dt
+t(tanx)=−secx=
dx
dt
+(tanx)t=secx.
I.F=e
∫tanxdx
=secx
Solution is t(I.F)=∫(I.F) secx dx
y
1
secx = tanx +c
Hence, option 'D' is correct.
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