Science, asked by Purvihotwani, 9 months ago

A brick of dimension 12m×10×5m is lying on the floor experience a force of 60N .Calculate the pressure.​

Answers

Answered by BrainlyNisha001
2

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We know, when force is constant, pressure ∞ 1/Area.

Therefore, pressure is maximum when area is minimum and vice versa.

By calculating the area of three faces, we get,

⇒A₁ = (20×10)= 200 sq m.

⇒A₂ = (10×5) = 50 sq m.

⇒A₃ = (20×5) = 100 sq m.

∴A₁ is maximum and A₂ is minimum.

∴Minimum pressure P₁ = F/A₁

= 30/200

= 0.15 Nm⁻².

∴Maximum pressure P₂ = F/A₂

= 30/50

= 0.6 Nm⁻². (Ans)

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Answered by Anonymous
1

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We know, when force is constant, pressure ∞ 1/Area.

Therefore, pressure is maximum when area is minimum and vice versa.

By calculating the area of three faces, we get,

⇒A₁ = (20×10)= 200 sq m.

⇒A₂ = (10×5) = 50 sq m.

⇒A₃ = (20×5) = 100 sq m.

∴A₁ is maximum and A₂ is minimum.

∴Minimum pressure P₁ = F/A₁

= 30/200

= 0.15 Nm⁻².

∴Maximum pressure P₂ = F/A₂

= 30/50

= 0.6 Nm⁻². (Ans)

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