Question

A brick of mass 2kg begins to slide down on a plane inclined at angle of 45 with the horizontal the force of friction

Answer 1

hope this helps you the frictional force will be equal to the component of weight parallel to the plane

Answer 2

Given:

Mass of brick,m=2 kg

$\theta=45^{\circ}$

To find:

Force of friction

Solution:

m=2 kg

$\theta=45^{\circ}$

We know that the force of friction between brick and plane is given by

$f=mgsin\theta$

Where $g=9.8 m/s^2$

Using the formula

$f=2\times 9.8sin45^{\circ}$

$f=13.86 N$

Hence, the force of friction between brick and plane=13.86 N