Question

A brick of weight 80 N stands upright on the ground as shown in figure. the pressure exerts on the ground by brick is (A) 51010–4 Nm–2 80 10cm (B)80×5×10–4 Nm–2 (C) 10 Nm–2 80510–4 (D) 80 Nm–2 10510–4

Answer 1

B)80x5x10-4Nm-2
................

Answer 2

Answer:

The correct answer will be -

(D) $\frac{80}{5\times 10\times 10^{-4}} \ Nm^{-2}$

Explanation:

Correction in the question -

The dimensions of the brick are -

Length = 10 cm

Breadth = 5 cm

Height = 20 cm

And the options are -

(A) $\frac{5\times 10\times 10^{-4}}{80} \ Nm^{-2}$

(B) $80\times 5\times 10\times 10^{-4} Nm^{-2}$

(C) $\frac{10}{80\times 5\times 10^{-4}} \ Nm^{-2}$

(D) $\frac{80}{5\times 10\times 10^{-4}} \ Nm^{-2}$

Solving -

We know that the pressure (P), Force (F), and the area (A) is related by -

$Pressure = \frac{Force}{Area}$

Calculating the area of the brick -

Area = $l\times b = 5 \times 10\ cm^2 = 5\times 10\times 10^{-4} \ m^2$

Given the force exerted is = 80 N

Then Pressure will be -

$= \frac{80}{5\times 10\times 10^{-4}} \ Nm^{-2}$

This will be our answer.

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