Question

A brick path 2m wide is to be laid around a rectangular flower bed,the quote to supply and lay the bricks is Rs.8 per sq.m.Calculate the (1.)Area of path,(2.)Perimeter of flower bed,(3.)Cost of laying path.

Answer 1

What are the dimensions of the flower bed?
If there's a picture of the bed in the book then please attach the photo to this question.

I'm assuming the dimensions of the flower bed to be L=10m & B=5m

As the path around the flower bed is 2m
The dimensions of the outer rectangle becomes L+4 & B+4
(See the attached photo for clarity.)
Dimensions of outer rectangle is 14m & 9m

1) Area of flower bed=a=L*B=10×5=50m²

2) Perimeter of flower bed=p=2(L+B)=2(10+5)
p=2×15=30m

3) Cost of laying path=C=Area of path*Rate
Area of path=Area of outer rectangle-Area of inner rectangle
Area of path=(14×9)-(10×5)=126-50=76m²

C=Area of path×Rate
C= 76×8 = Rs.608



NOTE:
If you found this answer to be helpful, please vote this answer as BRAINLIEST ANSWER to help me get some points. Thanks ☺️