Question

a walks at 4km/hr and 4hr.after his start B cycle after him 10 km/hr far from the start does catch with A

Answer 1

ANSWER:
26.6667km from start


EXPLANATION:
Velocity of A=v=4km/h
Velocity of B=V=10km/h

Distance covered by A in 4hrs=v*t=4*4=16km

Let distance to be covered by B to catch A=D
Let T be the time B takes to catch A
D=16km+(distance traveled by A after B has started chasing him)
D=16+(v*T)

Also D=[(velocity of B) *T]=V*T

Equating both equations, we get,
D=16+vT=VT
16+4T=10T
16=6T
T=16/6=2.6667hrs

D=VT=10×2.6667=26.6667km


NOTE:
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