A brother is eldet than his sister by 5 yrs if you add 6 to the fifth part of brother's age and 5 to third part of sister's age the result is same find their ages in linear equation in one variable
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Answer:
Hello!!
Step-by-step explanation:
Let the age of brother and sister be x and y respectively.
According to the question,
☛ Brother is elder than his sister by 5 years.
or
➜ x = 5 + y
➜ y = x - 5 -----(i)
Also,
☛ if you add 6 to fifth part of brother's age and 5 to the third part of sister's age the result is same.
or
➜ x/5 + 6 = 5 + y/3
➜ x + 30 / 5 = 15 + y / 3
➜ 3x + 90 = 75 + 5y
➜ 3x - 5y = -15 ------(ii)
From (i) , y = x - 5
Substituting y = x - 5 in eq.(ii)
➜ 3x - 5y = -15
➜ 3x - 5 ( x - 5 ) = -15
➜ 3x - 5x + 25 = -15
➜ 2x = 40
➜ x = 40/2
➜ x = 20
Substituting x = 20 in eq(i),
☛ y = x - 5
➜ y = 20 - 5
➜ y = 15
Hence, Age of elder brother is 20 years and age of his sister is 15 years.
I hope it was helpful.
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