Question

A brown mouse is mated with two female black mice. When each female has produced several litters of young, the first female has had 48 black and the second female has had 14 black and 11 brown young. Deduce the pattern of inheritance of coat color and the genotypes of all the parents (B-Black; b-brown).
a. male Bb; female 1, BB; female 2 Bb
b. male BB; female 1, BB; female 2 Bb
c. male Bb; female 1, BB; female 2 bb
d. none of the above ​

Note: Please provide the explanation or else do not answer

Answer 1

Answer:

Brown male mouse is mated with two female black mice. The first female has 48 black mice while the second female has 14 black and 11 brown young.

From the above result it can be deduced that: the gene for black coat is dominant (B) while the gene for brown coat is recessive (b).

In the first case, both the parents are homozygous.

Genotype of brown male is: b/b

Genotype of black female mouse is: B/B

The cross with first female:

b/b x B/B