Question

A bubble in glass slab (μ=1.5) when viewed from one side appears at 5 cm and 2 cm from other side, then thickness of slab is :

Answer 1

Let is take d1= 5cm and d2=2cm and x=refractive index=1.5Now. Actual width is the sum of real depth from the 2 sides= d1*x + d2*x= 2*1.5 + 5*1.5= 10.5cm

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Answer 2

If a bubble in glass slab (μ=1.5) when viewed from one side appears at 5 cm and 2 cm from other side, then thickness of slab is 10.5 cm.

Its explanation would be as follows:

Total apparent length is 5 + 2 = 7

Let's assume the real depth = x

Then, thickness of the slab would be =  

μ = real depth / apparent length

The equation would be x/y

which means, μ = x/y

x = μy = 1.5 X 7 = 10.5

Therefore, thickness of the slab is 10.5 cm.