Question

An ideal gas at 27°C is compressed adiabatically to 8/27 of its original volume.

Answer 1

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Answer 2

The rise in temperature is 375 K.

Explanation:

We have to calculate the rise in temperature.

Ideal gas equation for an adiabatic process,

$TV^{\gamma-1} =constant$

$T_{1} V^{\gamma-1}_{1}   =T_{2} V^{\gamma-1}_{2$

Given, $T_{1}=27^0C  =27+273=300K$, $V_{2} =\frac{8}{27} V_{1}$ and $\gamma=\frac{5}{3}$

Substitute the given values, we get

$300 K\times V^{5/3-1} =T_{2} (27/8V)^{5/3-1}$

$T=675K$

Therefore, change in temperature = 675-300=375 K .

Thus, rise in temperature is 375 K.

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Topic: an adiabatic process,

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