Physics, asked by rajc7421, 7 months ago

a bucket containing water is tied to one end of the rope 2.45 m long and rotated about the another end in a vertical circle. find the minimum velocity at the lowest point in order that water in the bucket may not slip.​

Answers

Answered by Anonymous
1

Answer:

the minimum velocity of the bucket so that water does not spill out is given by

v=

(rg)

=

(1.8∗10)

=

(18)

=4.2m/s

where r is length of rope and g is acceleration due to gravity

A bucket containing water is tied to one end of a rope of length 2.5 m and rotated about the other end in a vertical circle so that water does not spill even when bucet is upside down .

Explanation:

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