Math, asked by fbf13, 1 year ago

A bucket contains 20 1/4 litres of water. A small jug has a capacity of 3/4 litre. How many times the jug has to be filled with water from the bucket to get it emptied?

Answers

Answered by pratibhagupta2
94
20 1/4 litre = 3/4
81/4=3/4
81/4×4/3
27 litre
Answered by bhagyashreechowdhury
40

Given:

A bucket contains 20 1/4 litres of water

A small jug has a capacity of 3/4 litre.

To find:

How many times the small jugs of \frac{3}{4}\:litre has to be filled with water from the bucket to get it emptied?

Solution:

The quantity of water present inside the bucket = 20\frac{1}{4}\:litres = \frac{81}{4}\:litres

The capacity of each small jug = \frac{3}{4} \:litre

Let "n" represent the no. of times a small jug with a capacity of \frac{3}{4} \:litre has to be filled to empty the bucket.

Therefore, we will calculate the value of n as follows:

n = \frac{Litres\:of\:Water\:inside\:the\: bucket}{Capacity\:of\:each\:small\:jug}

\sf \implies n = \frac{\frac{81}{4} }{\frac{3}{4} }

\sf \implies n = \frac{81}{4} \:\times\: \frac{4}{3}

\sf \implies n = \frac{81}{3}

\sf \implies \bold{n = 27}

Thus, the small jug has to be filled 27 times with water from the bucket to get it emptied.

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