Question

A bucket has top and bottom diameters of 40 cm and 20 cm respectively. Find the volume of the bucket if it's depth is 12 cm. Also find the area of tin sheet used to make the bucket​

(tavishi didu ko answer klne do)

Answer 1

${\bf{Given :}}$

• A bucket has top and bottom diameters of 40 cm and 20 cm respectively.

${\bf{To Find :}}$

• Volume of bucket if it's depth is 12cm
• Area of the tin sheet used to make the bucket

${\bf{Solution :}}$

—Upper diameter = 40 cm

—Lower diameter = 20 cm

∴ Upper Radius (r1) = $\frac{40}{2} = 20 \: cm$

∴ Lower Radius (r2) = $\frac{20}{2} = 10 \: cm$

Depth or Height (h) = 12cm

VOLUME OF THE BUCKET :

➠ $\frac{\pi}{3} (r 1{}^{2} + r1 \: r2 \: + r2 {}^{2} )h$

➠ $\frac{22}{7} \times 3 \: ( {20}^{2} + 20 \times 10 + {10}^{2} ) \times 12cm^{3} </p><p></p><p>➠ [tex] \frac{22}{21} (400 + 200 + 100) \times 12cm^{3}$

➠ $\frac{22}{21} \times 700 \times 12 = 8800cm ^{3}$

Slant Height (l) =

➠ ${\bf{\sqrt{ {h}^{2} + (r1 - r2)^{2} }}}$

➠ ${\bf{\sqrt{12^{2} + (20 - 10)^{2} } = \sqrt{144 + 100}}}$

➠ ${\bf{\sqrt{244 \: cm}}}$

Surface Area of The Bucket =

➠ ${\bf{\pi(r1 + r2)l + \pi \: r \: 2 ^{2}}}$

➠ ${\bf{3.14(20 + 10) \: \: \sqrt{244 } + 3.14 \times {10}^{2} \: cm^{2}}}$

➠ ${\bf{3.14 × 30 × 15.62 + 3.14 × (10)² cm²}}$

➠ ${\bf{3.14 × 30 × 15.62 + 3.14 × 100cm²}}$

➠ ${\bf{1471.404 + 314 cm²}}$

➠ ${\bf{1785.404 cm² = 17.85404 dm²}}$

Cost of 1 dm² = ₹1.20 per dm²

∴ Total Cost = ₹12.85404 × 1.20

$\rightarrow$ ₹21.42 = ₹21.40

_____________________________________

$\huge\underline\blue{Thank \: Uh! ❤}$

Answer 2

here is your answer

$volume \: of \: bucket \: = \frac{1}{3} \pi \: height \: (r {2}{top} + Rtöp R²bottom) \\ \\☞ = \frac{1}{3} \pi \times 12( {20}^{2} + 20 \times 10 + {10}^{2} ) \\ \\☞ = 8800 {cm}^{3} \\ \\ ☞slant \: height \: \: 1 \: = √(20 - {10}^){2} + {12}^{2} \\ \\ ☞ = 15.62cm. \\ \\ ☞Tsa \: = \: \pi(R top +R bottom )1 \: + \: \pi(R²top +R²bottom ) \\ \\ ☞ = 3044.171 {cm}^{2} \\ \\ ☞cost \: = 120 \: \times \: 30.44171 \\ \\ ☞= rs.3653$

hope it is helpful for you ✅✔☑

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