A bucket is filled with water such that the weight of bucket alone is 25% its weight when it is filled with water.Now some of the water is removed frok the bucket and now the weigjt of nucket along with remaining water is 50% of original total weight .What part of the waywr wasvremoved from the bucket
Answers
HEYA!
The weight of bucket when filled with water is actually the weight of the bucket and the weight of the water together. In both 3/5 and 4/5 cases weight of the bucket is constant, let it be x.
Weight wen filed till 3/5: x+ weight of 3 parts ( each part 1/5 of the total capacity) of water. Let that be x+3y. It is 15kg.
Similarly in the 4/5 case, the equation would be x+4y=19kg.
Now, to the solving part,
x+3y=15
x= 15-3y.
Now substitute this in the second equation,
x+4y= 15-3y+4y=19.
15+y=19.
y= 4.
That is, one part of water weighs 4kg. Similarly frm the equation you'll get x, the weight of the bucket to be 3kg.
Now when filled to capacity the weight will be weight of the bucket and weight of five parts (full is5/5) of water: 3+4*5=23.
HOPE IT WORKS!!