a bucket is in the form of frustrum of a cone with/capacity of 12308.8 cm3. the radii of the top and/bottom circular end are 20 and 12 cm. find the hieght of the bucket and area of the metal sheet used
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Volume of frustum= 1/3πh(r2+r22+r1r2)
this question is solve by thus process
1/3πh(r2+r22+r1r2) = 12308.8
1/3×22/7×h(400+144+20×12)= 12308.8
1/3×22/7×h(780)= 12308.8
this question is solve by thus process
1/3πh(r2+r22+r1r2) = 12308.8
1/3×22/7×h(400+144+20×12)= 12308.8
1/3×22/7×h(780)= 12308.8
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Answer, may this help you
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